Electrical fundamentals · Illustrated guide

Power Factor Explained

Why do two loads using the same kW draw different current? Understand power factor, reactive power and how capacitor banks change the numbers.

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Imagine two installations both using 100 kW. One runs at power factor 1.0; the other at 0.8. They produce the same useful electrical power, but the second needs more current from the supply.

Power factor tells us how effectively apparent power (kVA) is being used to supply active power (kW). It helps engineers size feeders, understand reactive demand and estimate power-factor correction.

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01 · Definition

What is power factor, in simple terms?

Power factor (PF) is active electrical power divided by apparent power. It ranges from zero to one for the loads in this guide. A value closer to one means less current is needed to deliver the same kW at the same voltage.

PF=PSPF=\frac{P}{S}

For a balanced, sinusoidal AC system, PF is also the cosine of the phase angle between voltage and current. That is where the familiar term cos φ comes from.

PF=cos⁡φ(sinusoidal conditions)PF=\cos\varphi\quad\text{(sinusoidal conditions)}
Simple idea: 0.80 PF means the active kW are 80% of the apparent kVA numerically. It does not mean 20% of electricity is necessarily wasted as heat.
02 · Three quantities

How P, Q and S are connected

P

Active (kW)

Energy actually converted to work, heat or light.

Q

Reactive (kvar)

Power exchanged by magnetic or electric fields.

S

Apparent (kVA)

Total volts × RMS amps carried by the source.

For a sinusoidal system, P and Q form perpendicular sides of a power triangle; S is its hypotenuse.

S=P2+Q2S=\sqrt{P^2+Q^2}
The power triangle changes with PFKeep active power at 100 kW
P = 100 kWQ = 75.0 kvarS = 125.0 kVAφ ≈ 36.9°0
For a fixed useful 100 kW, decreasing PF increases the reactive kvar and apparent kVA. Increasing PF toward unity reduces the height and hypotenuse. The diagram shows an inductive (lagging), sinusoidal load.

Try moving the slider. With P fixed at 100 kW, improving PF reduces Q and S. This also reduces current for the same supply voltage, assuming no other change to the load.

03 · Phase relationship

Why the voltage–current angle matters

In a purely resistive load, voltage and current rise and fall together; the angle φ is approximately zero and displacement power factor is one.

Inductive loads such as motors and transformers typically make fundamental current lag voltage. Capacitive loads make fundamental current lead voltage. Both can have the same PF magnitude, but their reactive power signs are opposite.

Voltage and current phasorsIllustrative inductive load
V (reference)I (lagging)φAngle shown is illustrative, not an installation measurement.
Inductive loads typically make fundamental current lag the voltage. With capacitive loads the current leads instead. The cosine of this angle is the displacement power factor; distortion may make true PF different.
Lagging / inductiveQ positive (+)Leading / capacitiveQ negative (−)
04 · Causes

Why does power factor decrease?

Motors, transformers and other magnetic equipment need magnetizing current. That extra current may increase the kVA delivered by the transformer without increasing the useful active kW by the same amount.

The power factor of an installation varies as equipment starts, stops or runs at different loading. A lightly loaded motor may have a poorer PF than the same motor near rated load.

Capacitive loads and heavily compensated installations can also have a leading PF. Low PF is not always an inductive-load problem.
05 · Consequences

What changes when PF is low?

For a fixed supply voltage and active power, a lower PF means a larger apparent power and current. That can increase losses and voltage drop in conductors and use up capacity in transformers and switchgear.

I=P×10003 ULL PF(three phase)I=\frac{P\times1000}{\sqrt3\,U_{LL}\,PF}\quad\text{(three phase)}

For single-phase AC, use line-to-neutral voltage without the √3 multiplier. Reactive-energy charging or power-factor penalties depend on the actual supplier and contract; don't assume a universal limit.

06 · Correction

How a capacitor bank can improve PF

An inductive load typically draws positive reactive power. A correctly sized capacitor bank provides reactive power locally, reducing the reactive power the upstream supply needs to deliver.

For an inductive load corrected to another lagging target, the familiar sizing formula is:

Qc=P(tan⁡φ1−tan⁡φ2)Q_c=P\big(\tan\varphi_1-\tan\varphi_2\big)

Here P is the existing active electrical power (kW), φ₁ is the old phase angle, φ₂ is the desired angle, and Qc is the ideal compensation in kvar.

Important: if the load is already leading, more capacitors may make matters worse. A leading-to-lagging change may require inductive compensation. KiloVolt uses signed kvar internally to detect that situation.

07 · Worked example

100 kW: correct PF from 0.80 to 0.95

Assume a balanced, sinusoidal, inductive three-phase load drawing 100 kW at 400 V line-to-line. We want to improve PF from 0.80 lagging to 0.95 lagging.

Step 1 — Initial reactive power

Q1=100×tan⁡(arccos⁡0.80)=75 kvarQ_1=100\times\tan(\arccos 0.80)=75\ \mathrm{kvar}

Step 2 — Target reactive power

Q2=100×tan⁡(arccos⁡0.95)≈32.87 kvarQ_2=100\times\tan(\arccos 0.95)\approx32.87\ \mathrm{kvar}

Step 3 — Ideal capacitor bank rating

Qc=75−32.87≈42.13 kvarQ_c=75-32.87\approx42.13\ \mathrm{kvar}

Step 4 — Current before and after

I1=125×10003×400≈180.42 AI_1=\frac{125\times1000}{\sqrt3\times400}\approx180.42\ \mathrm A
I2=(100/0.95)×10003×400≈151.93 AI_2=\frac{(100/0.95)\times1000}{\sqrt3\times400}\approx151.93\ \mathrm A

The theoretical correction is approximately 42.13 kvar, and the upstream current falls by approximately 28.49 A for this load and these assumptions.

08 · Practical engineering

Does a 42.13 kvar result mean buying a 42.13 kvar capacitor bank?

No. The calculation gives a theoretical reactive-power requirement at one operating point, not a final capacitor-bank specification. Real capacitor steps are available in standard commercial sizes, and their delivered kvar depends on terminal voltage and rating.

Variable installations may need an automatic multistep bank; fixed loads may be treated differently. Before selection, check the load profile, switching, harmonic distortion, possible resonance, detuned reactors, inrush, protection, ventilation and required connection arrangements.

Professional caution: harmonic-rich systems (for example, with many VFDs) need additional analysis before applying capacitors. Improper correction equipment can create resonance and damage components.
09 · Limits

Displacement PF is not always true PF

For an undistorted sinusoidal waveform, PF = cos φ. But modern nonlinear loads can distort current waveforms. In that case, true power factor depends on both fundamental phase displacement and distortion.

This calculator uses the conventional sinusoidal power triangle. It does not calculate harmonics or true PF for distorted waveforms. Those belong in our future dedicated Power Quality tools.

10 · Practical checklist

Common mistakes to avoid

Confusing kW, kVA and kvar

These represent active, apparent and reactive power respectively. They are not interchangeable.

Assuming improved PF reduces active power

Power-factor correction usually reduces upstream kVA and current, not the useful work or active power required by the load.

Using the three-phase formula for a single-phase circuit

The √3 factor applies to balanced three-phase calculations with line-to-line voltage, not single-phase calculations.

Ignoring leading versus lagging power factor

Check the sign of reactive power before choosing capacitive or inductive compensation.

Sizing a capacitor bank using only theoretical kvar

Also assess harmonics, varying loads, actual system voltage, switching and equipment ratings.

Further reading: Schneider Electric — Theoretical principles to improve power factor (external engineering reference).

READY TO CALCULATE?

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Enter existing kW or kVA, current cos φ, target cos φ and supply voltage to calculate P, Q, S, line current and theoretical reactive correction.

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